Changing Unit of Measurement.ppt
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1、week3,1,Changing Unit of Measurement,A linear transformation changes the original value x into a new variable xnew . xnew is given by an equation of the form,Example 1.21 on page 45 in IPS.(i) A distance x measured in km. can be expressed inmiles as follow, .(ii) A temperature x measured in degrees
2、Fahrenheit can beconverted to degrees Celsius by,week3,2,Effect of a Linear Transformation,Multiplying each observation in a data set by a number b multiplies both the measures of center (mean, median, and trimmed means) by b and the measures of spread (range, standard deviation and IQR) by |b| that
3、 is the absolute value of b.Adding the same number a to each observation in a data set adds a to measures of center, quartiles and percentiles but does not change the measures of spread.Linear transformations do NOT change the overall shape of a distribution.,week3,3,week3,4,Example 1,A sample of 20
4、 employees of a company was taken and their salaries were recorded. Suppose each employee receives a $300 raise in the salary for the next year. State whether the following statements are true or false. The IQR of the salaries will be unchanged increase by $300 be multiplied by $300 The mean of the
5、salaries will be unchanged increase by $300 be multiplied by $300,week3,5,Density curves,Using software, clever algorithms can describe a distribution in a way that is not feasible by hand, by fitting a smooth curve to the data in addition to or instead of a histogram. The curves used are called den
6、sity curves.It is easier to work with a smooth curve, because histogram depends on the choice of classes.Density CurveDensity curve is a curve that is always on or above the horizontal axis. has area exactly 1 underneath it. A density curve describes the overall pattern of a distribution.,week3,6,Th
7、e area under the curve and above any range of values is the relative frequency (proportion) of all observations that fall in that range of values.Example: The curve below shows the density curve for scores in an exam and the area of the shaded region is the proportion of students who scores between
8、60 and 80.,week3,7,Median and mean of Density Curve,The median of a distribution described by a density curve is the point that divides the area under the curve in half. A mode of a distribution described by a density curve is a peak point of the curve, the location where the curve is highest. Quart
9、iles of a distribution can be roughly located by dividing the area under the curve into quarters as accurately as possible by eye.,week3,8,Normal distributions,An important class of density curves are the symmetric unimodal bell-shaped curves known as normal curves. They describe normal distribution
10、s.All normal distributions have the same overall shape.The exact density curve for a particular normal distribution is specified by giving its mean (mu) and its standard deviation (sigma).The mean is located at the center of the symmetric curve and is the same as the median and the mode.Changing wit
11、hout changing moves the normal curve along the horizontal axis without changing its spread.,week3,9,The standard deviation controls the spread of a normal curve.,week3,10,There are other symmetric bell-shaped density curves that are not normal e.g. t distribution. Normal density function is mathemat
12、ical model of process producing data. If histogram with bars matching normal density curve, data is said to have a normal distribution.Notation: A normal distribution with mean and standard deviation is denoted by N(, ).,week3,11,The 68-95-99.7 rule,In the normal distribution with mean and standard
13、deviation , Approx. 68% of the observations fall within of the mean . Approx. 95% of the observations fall within 2 of the mean . Approx. 99.7% of the observations fall within 3 of the mean .,week3,12,Example 1.23 on p72 in IPS,The distribution of heights of women aged 18-24 is approximately N(64.5,
14、 2.5), that is ,normal with mean = 64.5 inches and standard deviation = 2.5 inches.The 68-95-99.7 rule says that the middle 95% (approx.) of women are between 64.5-5 to 64.5+5 inches tall.The other 5% have heights outside the range from 59.5 to 69.5 inches, and 2.5% of the women are taller than 69.5
15、 .Exercise:1) The middle 68% (approx.) of women are between _to _inches tall.2) _% of the women are taller than 66.75. 3) _% of the women are taller than 72.,week3,13,Standardizing and z-scores,If x is an observation from a distribution that has mean and standard deviation , the standardized value o
16、fx is given by A standardized value is often called a z-score.A z-score tells us how many standard deviations the original observation falls away from the mean of the distribution.Standardizing is a linear transformation that transform the data into the standard scale of z-scores. Therefore, standar
17、dizing does not change the shape of a distribution, but changes the value of the mean and stdev.,week3,14,Example 1.26 on p61 in IPS,The heights of women is approximately normal with mean = 64.5 inches and standard deviation = 2.5 inches. The standardized height isThe standardized value (z-score) of
18、 height 68 inches isor 1.4 std. dev. above the mean.A woman 60 inches tall has standardized heightor 1.8 std. dev. below the mean.,week3,15,The Standard Normal distribution,The standard normal distribution is the normal distribution N(0, 1) that is, the mean = 0 and the sdev = 1 . If a random variab
19、le X has normal distribution N(, ), then the standardized variable has the standard normal distribution.Areas under a normal curve represent proportion of observations from that normal distribution. There is no formula to calculate areas under a normal curve. Calculations use either software or a ta
20、ble of areas. The table and most software calculate one kind of area: cumulative proportions . A cumulative proportion is the proportion of observations in a distribution that fall at or below a given value and is also the area under the curve to the left of a given value.,week3,16,The standard norm
21、al tables,Table A gives cumulative proportions for the standard normal distribution. The table entry for each value z is the area under the curve to the left of z, the notation used is P( Z z). e.g. P( Z 1.4 ) = 0.9192,17,Standard Normal Distribution,The table shows area to left of z under standard
22、normal curve,week3,18,The standard normal tables - Example,What proportion of the observations of a N(0,1) distribution takes valuesa) less than z = 1.4 ?b) greater than z = 1.4 ?c) greater than z = -1.96 ?d) between z = 0.43 and z = 2.15 ?,week3,19,Properties of Normal distribution,If a random vari
23、able Z has a N(0,1) distribution then P(Z = z)=0. The area under the curve below any point is 0. The area between any two points a and b (a b) under the standard normal curve is given byP(a Z b) = P(Z b) P(Z a)As mentioned earlier, if a random variable X has a N(, ) distribution, then the standardiz
24、ed variable has a standard normal distribution and any calculations about Xcan be done using the following rules:,week3,20,P(X = k) = 0 for all k.The solution to the equation P(X k) = p isk = + zpWhere zp is the value z from the standard normal table that has area (and cumulative proportion) p below
25、 it, i.e. zp is the pth percentile of the standard normal distribution.,week3,21,Questions,1. The marks of STA221 students has N(65, 15) distribution. Find the proportion of students having marks (a) less then 50. (b) greater than 80.(c) between 50 and 80.2. Example 1.30 on page 65 in IPS:Scores on
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