SAE J 944-1968 STEERING CONTROL SYSTEM - PASSENGER CAR - LABORATORY TEST PROCEDURE.pdf
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1、STEERING CONTROL SYSTEM PASSENGER CAR-LABORATORYTEST PROCEDURE-SAE J944 JUN80- - Reproduced By GLOBAL J.=. ENGINEERING DOCUMENTS.- .i! With The Permission Of SAE? Under Royalty AgreementSAE Recommended PracticeReport of the AUlOmolIV(aiclYCommmee. approved Dembcr 1965. last revised :o“cmber 1968. re
2、affinned wnhout change June 1980.I. SCO/N-This SAE Recommended Practice describes a laboratorv testprocedure for evaluating- the characteristics of steering control systemsndersimulated driver impact conditions. The test procedure emplovs a torso shaped bodv block which is impacted against the steer
3、ing control sYStem.2. Definition-For the purposes of this recommended practice. the steeringcontrol svstem is detined as that portion of the vehicle steering mechanismhat mav affect the occupant impact characteristics.3. Riftnnet-SAE 9i7.4. ltmu to bt Determined4.1 Impact velocity of the body block.
4、4.2 Peak resultant force of the impact.5. Test Equipment and InstrumentDtian5.1 Body Block-The complete body block shall have the followingcharacteristics:BEST COpy AVAILABLE.5.1.1 SPRISG RATE-I07-143kit cm. when the cheslis loaded b a 4in.wide b 15 in. lonlt (10.0 b“ 38.0 ;m I beam. 90 delt to the
5、lonltitudinal a.xis ofthe bod“ block.adparaliel to the backing plate(Fig. II. The center of thebeam is placed 18.0 = 0.25 in. (45. i = 0.63 cm 1 from the top of the head.centered laterally. and preloaded to 5 Ib (2.26 kg) including the weight of thebeam. to establish baseline penetration. Test speed
6、 is 10 = 2 in. minute(25.0 = 5 cmiminute). The load is measured when the beam has moved0.50 in. (12.7 cm) into the body block from the baseline and the spring rate isobtained b“ doubling this load.5.1.2 “EIGHT-The bod block shall weilth i5 + 5 -Olb (33.9i + 2.26-0 kgl. . -5.1.3 BODY BLOCK CE!oolER O
7、F GRAvm-The center of !travitv of the complete bod“ block shall be 21.i = 0.25 in. (55.12 = 0,63c)fr;m the top ofthe head.5.1 A MOMEST OF ISERTIA-The moment of inenia around the lateral axisthrough the center of gravity of the complete body block shall be20 = 2 in.-Ib.sec(23 = 2.3 cm-kltsec).5.1.5 C
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