GOST R ISO 11843-5-2012 Statistical methods Capability of detection Part 5 Methodology in the linear and non-linear calibration cases《统计方法 检测能力 第5部分 线性和非线性校准情况下的方法学》.pdf

《GOST R ISO 11843-5-2012 Statistical methods Capability of detection Part 5 Methodology in the linear and non-linear calibration cases《统计方法 检测能力 第5部分 线性和非线性校准情况下的方法学》.pdf》由会员分享，可在线阅读，更多相关《GOST R ISO 11843-5-2012 Statistical methods Capability of detection Part 5 Methodology in the linear and non-linear calibration cases《统计方法 检测能力 第5部分 线性和非线性校准情况下的方法学》.pdf（20页珍藏版）》请在麦多课文档分享上搜索。

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5、tent organic pollutants.4)ELISA enzyme-linked immunosorbent assay.1 11843-52012 3534-2 . . 2. (ISO 3534-2, Statistics Vocabulary and symbols Part 2: Applied statistics) 3534-3 . . 3. - (ISO 3534-3, Statistics Vocabulary and symbols Part 3: Design of experiments) 5725-1 ( ) . 1. (ISO 5725-1, Accuracy

6、 (trueness and precision) of measurementmethods and results Part 1: General principles and definitions) 11843-1:1997 . 1. (ISO 11843-1:1997, Capability of detection Part 1: Terms and definitions) 11843-2:2000 . 2. - (ISO 11843-2:2000, Capability of detection Part 2: Methodology in the linear calibra

7、tion case)3 3534 ( ), 5725-1, 11843-1, :3.1 ; xc(critical value of the netstate variable): X, c97 , (. 1). 11843-1:1997, 3.103.2 (minimum detectable value of the net state variable); xd: X , (1 c98) , - . 11843-1:1997 11843-1:1997/Cor. 1:2003(. 1).2 11843-52012xc ; xd ; X ; c97 X=0;c98 - X=xd; 1 118

8、43-1:1997 - . 1 - , , - 1 11843-1. 1 X = 0 () X = xd()3.3 ( ) (precision): - - . 1 - . 2 ( 3534-2). 3 - .3.4 ( ) (precision profile): - .3.5 (response variable); Y: , . 3534-3:1999, 1.2 1 11843 - Z. 2 Y , - . c115X(X) c114(X) -.3.6 (precision profile of response variable): ( ), , - (, - ), , .3.7 (n

9、et state variable); X: Z z0. 11843-1:1997, 4 X () , , c115X(X)c114X(X) .4 ( ) Y ( X). - Y X (. 2 1, 2). 3 c115Y(X) c115X(X) |dY/dX|: c115X(X)=c115Y(X)/|dY/dX|. c114X(X) c114X(X)=c114Ydd()XYXYX.(1) (1) c114Y(X)X c114X(X). |dY/dX| - .3 11843-52012 2 1 - (Y = ), c114X(X) c114Y(X). , Y/X=|dY/dX|=a, Y = . 2 (1) X=0, , c114X(X) X , - c115X(X) ( c115X(X)=c114Y(X)Y/|dY/dX|).5 5.1 . xc xc= kcc115X(0), (2) kc c97;c115X(0) X =0. c115X(0) = c115Y(0)/|dY/dX| (2) xc= kcc115Y(0)/|dY/dX|. xd xd= xc+kdc115X(xd), (3) kd c98;c115X(xd)