DIN ISO 18314-2-2017 Analytical colorimetry - Part 2 Saunderson correction solutions of the Kubelka-Munk equation tinting strength hiding power (ISO 18314-2 2015)《分析比色法 第2部分 Saunde.pdf
《DIN ISO 18314-2-2017 Analytical colorimetry - Part 2 Saunderson correction solutions of the Kubelka-Munk equation tinting strength hiding power (ISO 18314-2 2015)《分析比色法 第2部分 Saunde.pdf》由会员分享,可在线阅读,更多相关《DIN ISO 18314-2-2017 Analytical colorimetry - Part 2 Saunderson correction solutions of the Kubelka-Munk equation tinting strength hiding power (ISO 18314-2 2015)《分析比色法 第2部分 Saunde.pdf(21页珍藏版)》请在麦多课文档分享上搜索。
1、April 2017 English price group 12No part of this translation may be reproduced without prior permission ofDIN Deutsches Institut fr Normung e. V., Berlin. Beuth Verlag GmbH, 10772 Berlin, Germany,has the exclusive right of sale for German Standards (DIN-Normen).ICS 87.060.10!%c| 0 and x - x0 090 0 a
2、nd x - x00DIN ISO 18314-2:2017-04 13 a() are factors:aa KWKW KW() ()=+ +01 2323(33)Tables of coefficients K1, K2, and K3for standard shade depths 1/1, 1/3, 1/9, 1/25, and 1/200 are given in Annex A for standard illuminant D65 and a 10 standard observer and in Annex B for standard illuminant C and a
3、2 standard observer.W =0100(34)0is the closest angle in the table below the hue angle (in degrees). The coefficients K1, K2, and K3of 0are used in Formula (33).From Formula (6) and the Saunderson-corrected reflectance R()* for the test sample, calculate the corresponding Kubelka-Munk functions F() f
4、or the test and reference samples. Adjust the B values for the white reductions of the test and reference samples to the specified standard shade depth by varying the mass fractions mtand mr, and use the resulting values of mtand mrto determine modified Kubelka-Munk functions F() as follows:FFmmtttt
5、 ()=() (35)FFmmrrrr()=() (36)Solving Formula (6) for R, calculate modified reflectance spectra R()* from these modified Kubelka-Munk functions F() and subject the spectra to an inverse Saunderson correction (see Clause 3) to obtain modified R() that include surface effects. From these spectra calcul
6、ate the B values for the white reductions of the test and reference samples.Vary the mass fractions mtand mrindependently of one another, preferably by an iterative mathematical procedure, until the shade depth of the white reductions of the test and reference samples equals that of the specified st
7、andard shade depth, i.e. until:Bt= 0 for mt andBr= 0 for mrThen calculate the relative tinting strength from:Cmmrelrt=100 (37)Calculate the residual colour difference (see Reference 6) from those reflectance spectra Rt() and Rr() for the test and reference samples that result in equalization of the
8、shade depth.6 Determination of hiding power of pigmented media6.1 GeneralThe hiding power value indicates what area, in square metres, of a given contrast substrate can be coated with the unit of quantity of the sample in such a manner that a specified hiding criterion is achieved. The hiding criter
9、ion shall be an agreed colour difference between the two contrasting areas of the coated contrast substrate. A Eab*=1 is commonly applied. For achromatic coatings, a contrast ratio of 0,98 is used to take into account the 2 % threshold value for brightness perception by the human eye. DIN ISO 18314-
10、2:2017-04 14 The substrates have of course to be standardized for an exact method of determination. Values of reflectance close to zero for black and 0,8 for white substrates are employed.The parameter determined by all methods is the minimal film thickness hDnecessary to fulfill the criteria used.
11、The reciprocal of this parameter is equivalent to hiding power value D = 1/hD.The hiding power value can be determined and specified in the following ways: hiding power value Dvin square metres per litre; hiding power value Dm, in square metres per kilogram.Dvand Dmeach indicate the area of the cont
12、rast substrate concerned, in square metres, which can be coated with 1 l or 1 kg of the pigmented medium so as to ensure hiding (in the sense of the hiding criterion).Colourimetric methods for the determination of the hiding power use the general solutions for the Kubelka-Munk equation in combinatio
13、n with an iterative program to determine the necessary film thickness to fulfill the hiding power criteria chosen. This is the most straightforward way leading to the best results.It is possible to work with two non hiding layers on white and black substances or with a hiding layer in combination wi
14、th a non hiding one on a black or white substrate. The method should preferably be determined by reviewing the data available.6.2 Example for white or light coloured paints with a contrast ratio of 0,98 as hiding power criterionThe following equations specify a method applicable for white and light-
15、coloured paints where the colour differences between black and white substrates is determined by the lightness differences. In such cases R() can be replaced by R(Y) with R(Y) being the tristimulus value Y divided by 100.The following equations give the reflectance over a black R(Y)B* and white R(Y)
16、* substrate:RYYRYY YSYh*()1a( )()b() cothb( ) ()B=+0*(38)RYRY YY YSYhYRYY*()1()a( )b()cothb()()a( )()b()co=+00*tthb()()YSYh(39)A reflectance of 0,8 is assumed as RY()0*. So RY RY()B*/() is with a contrast ratio of 0,98:RYRYaY YYSYhaY bY*()()() 0, b( )cothb( )( )() ()cothB0,98=+8 b()() ()()coth ()()
17、)YSYh aY bY bY SYh09809810809, ,( ,+= 8 (40)this can be solved tohbY SYVYY098,=+1()()arccoth0,02 ()1,568 b( )(41)DIN ISO 18314-2:2017-04 15 withVY aY aY() 3,136 ()10,981 0,8( )2,5084= (42)The equations above give a result ofDYYSYVYbY()b( )( )arccoth0,02 ()1,568 ()=+(43)a(Y), b(Y), and S(Y) have the
18、same meaning as defined in Formulae 12 to 15.7 Repeatability and reproducibilityTypically the choice of the correct sampling and the preparation of the test specimen have influences on the result of the measurement far superior to those of the calculation applied. It shall be ascertained by suitable
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