ASHRAE HVAC APPLICATIONS IP ADD AND CORR-2015 Additions and Corrections.pdf
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1、A.1ASHRAE HANDBOOKAdditions and CorrectionsThis report includes additional information, and technical errorsfound between June 15, 2012, and April 1, 2015, in the inch-pound(I-P) editions of the 2012, 2013, and 2014 ASHRAE Handbookvolumes. Occasional typographical errors and nonstandard symbollabels
2、 will be corrected in future volumes. The most current list ofHandbook additions and corrections is on the ASHRAE web site(www.ashrae.org).The authors and editor encourage you to notify them if youfind other technical errors. Please send corrections to: HandbookEditor, ASHRAE, 1791 Tullie Circle NE,
3、 Atlanta, GA 30329, ore-mail mowenashrae.org.2012 HVAC Systems and Equipmentp. 25.1, Fig. 1. Point E was omitted. The correct figure appearsbelow.p. 26.2, Eq. (2a). In the rightmost fraction, change msto me.p. 26.12, Example 2. Flow rate for ethylene glycol should be ingpm.p. 26.12, Fig. 13. The cor
4、rected figure is given below.p. 41.3, Fig. 3. Replace parts B and C of the graphic with the hori-zontal polymer tube shown on p. A.2.p. 44.8, Table 1. In both equations for flow and head, change theminuses to equals signs.p. 51.24, Fig. 25. The bottom right line should have the dischargearrow pointi
5、ng to the left, and the charge arrow pointing to the right.The corrected figure is shown on p. A.2.2013 Fundamentalsp. 1.13, 2nd col. Above Eq. (38), change “td( p, w)” to “td( p, W ).”p. 1.14, 1st col. In the table for Situation 2, 3rd line, Comments col-umn, change “td” to “t.”p. 4.21, Solution fo
6、r Example 10, starting in 3rd para. Compute hiusing Eq. (T8.5a). Delete fsand its value. Nudshould be 248.3, andhishould be 1248 Btu/hft2F. Compute housing Eq. (T9.10a).Change Ra to 74 574, Nu to 7.223, hoto 3.643 Btu/hft2F, and theequation for hotto 0.643 + 0.757 = 1.400 Btu/hft2F. Change the lastp
7、aragraph in the example as follows:Solving for domakes the left side of Equation (42) equal to the rightside, and gives do= 1.576 in. Now, using the new value of 1.576 in. forthe outer diameter, the new values of hoand hotare 0.680 Btu/hft2Fand 1.437 Btu/hft2F, respectively. The updated value of doi
8、s 1.857 in.Repeating the process several times results in a final value of do= 1.733in. Thus, an outer diameter of 1.7874 in. (corresponding to an insula-tion radial thickness of 0.5 in.) keeps the outer surface temperature at75.4F, higher than the dew point. Another method is to use Equation(42) to
9、 solve for tofor values of docorresponding to available insulationthicknesses and using the insulation thickness that keeps toabove thedew-point temperature.p. 9.19, 1st col. For Eq. (71), remove the minus sign before “(tsk93.2).” In the following definitions, add that tbsetshould beFig. 1 Dehumidif
10、ication Process Points(2012 HVAC Systems and Equipment, Ch. 25, p. 1)Fig. 13 The Psychrometric Processes of Exchangers in Series Mode(Moffitt 2011)(2012 HVAC Systems and Equipment, Ch. 26, p. 12)A.2 20122014 ASHRAE Handbook Additions and Corrections97.68F. In Eq. (72), change the minus in the denomi
11、nator to aplus.Ch. 14, climate data table for Esbjerg, Denmark. Please use the2009 data for this location.p. 15.17, Eq. (13). The equals sign belongs after “SHGC().”p. 15.29, Example 6, Solution. The first equation should read qs=qb+ qd.p. 15.32, Eq. (40). Change “min(1,0.02 )” to “min(1.2,60)/60.”
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