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    ASHRAE HVAC APPLICATIONS IP ADD AND CORR-2015 Additions and Corrections.pdf

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    ASHRAE HVAC APPLICATIONS IP ADD AND CORR-2015 Additions and Corrections.pdf

    1、A.1ASHRAE HANDBOOKAdditions and CorrectionsThis report includes additional information, and technical errorsfound between June 15, 2012, and April 1, 2015, in the inch-pound(I-P) editions of the 2012, 2013, and 2014 ASHRAE Handbookvolumes. Occasional typographical errors and nonstandard symbollabels

    2、 will be corrected in future volumes. The most current list ofHandbook additions and corrections is on the ASHRAE web site(www.ashrae.org).The authors and editor encourage you to notify them if youfind other technical errors. Please send corrections to: HandbookEditor, ASHRAE, 1791 Tullie Circle NE,

    3、 Atlanta, GA 30329, ore-mail mowenashrae.org.2012 HVAC Systems and Equipmentp. 25.1, Fig. 1. Point E was omitted. The correct figure appearsbelow.p. 26.2, Eq. (2a). In the rightmost fraction, change msto me.p. 26.12, Example 2. Flow rate for ethylene glycol should be ingpm.p. 26.12, Fig. 13. The cor

    4、rected figure is given below.p. 41.3, Fig. 3. Replace parts B and C of the graphic with the hori-zontal polymer tube shown on p. A.2.p. 44.8, Table 1. In both equations for flow and head, change theminuses to equals signs.p. 51.24, Fig. 25. The bottom right line should have the dischargearrow pointi

    5、ng to the left, and the charge arrow pointing to the right.The corrected figure is shown on p. A.2.2013 Fundamentalsp. 1.13, 2nd col. Above Eq. (38), change “td( p, w)” to “td( p, W ).”p. 1.14, 1st col. In the table for Situation 2, 3rd line, Comments col-umn, change “td” to “t.”p. 4.21, Solution fo

    6、r Example 10, starting in 3rd para. Compute hiusing Eq. (T8.5a). Delete fsand its value. Nudshould be 248.3, andhishould be 1248 Btu/hft2F. Compute housing Eq. (T9.10a).Change Ra to 74 574, Nu to 7.223, hoto 3.643 Btu/hft2F, and theequation for hotto 0.643 + 0.757 = 1.400 Btu/hft2F. Change the lastp

    7、aragraph in the example as follows:Solving for domakes the left side of Equation (42) equal to the rightside, and gives do= 1.576 in. Now, using the new value of 1.576 in. forthe outer diameter, the new values of hoand hotare 0.680 Btu/hft2Fand 1.437 Btu/hft2F, respectively. The updated value of doi

    8、s 1.857 in.Repeating the process several times results in a final value of do= 1.733in. Thus, an outer diameter of 1.7874 in. (corresponding to an insula-tion radial thickness of 0.5 in.) keeps the outer surface temperature at75.4F, higher than the dew point. Another method is to use Equation(42) to

    9、 solve for tofor values of docorresponding to available insulationthicknesses and using the insulation thickness that keeps toabove thedew-point temperature.p. 9.19, 1st col. For Eq. (71), remove the minus sign before “(tsk93.2).” In the following definitions, add that tbsetshould beFig. 1 Dehumidif

    10、ication Process Points(2012 HVAC Systems and Equipment, Ch. 25, p. 1)Fig. 13 The Psychrometric Processes of Exchangers in Series Mode(Moffitt 2011)(2012 HVAC Systems and Equipment, Ch. 26, p. 12)A.2 20122014 ASHRAE Handbook Additions and Corrections97.68F. In Eq. (72), change the minus in the denomi

    11、nator to aplus.Ch. 14, climate data table for Esbjerg, Denmark. Please use the2009 data for this location.p. 15.17, Eq. (13). The equals sign belongs after “SHGC().”p. 15.29, Example 6, Solution. The first equation should read qs=qb+ qd.p. 15.32, Eq. (40). Change “min(1,0.02 )” to “min(1.2,60)/60.”

    12、Add Barnaby et al. (2009) to the list of sources cited below.p. 16.24, Table 8. The corrected table appears above.p. 16.24, Example 5. The houses flow coefficient c should be4370 cfm/(in. of water)n. In the Solution, Csshould be 0.001478 (in.of water)/Fnand Cwshould be 0.001313 (in. of water)/mphn.C

    13、onsequently, the second and third equations should be as follows:Qs= 4370(0.001478)68 (2)0.67= 110 cfmQw= 4370(0.001313)(0.64 8.9)1.34= 59 cfmQ is thus 125 cfm = 7490 ft3/h, and the final equation should beI = (7490 ft3/h)/(12,000 ft3) = 0.62 achpp. 16.24-25, Example 6. The houses flow coefficient c

    14、 should be6890 cfm/(in. of water)n. In the Solution, Csshould be 0.00893 (in.of water)/Fnand Cwshould be 0.001074 (in. of water)/mphn.Consequently, the second and third equations should be as follows:Qs= 6890(0.00893)(29)0.6= 46 cfmQw= 6890(0.001074)(0.50 2.9)1.34= 12 cfmQ is thus 48 cfm = 2880 ft3/

    15、h, and the final equation should beI = (2880 ft3/h)/(9000 ft3) = 0.32 achp. 16.25, Example 7. The houses flow coefficient c should be8740 cfm/(in. of water)n. In the Solution, Csshould be 0.001791 (in.of water)/Fnand Cwshould be 0.001295 (in. of water)/mphn.Consequently, the second and third equatio

    16、ns should be as follows:Qs= 8740(0.001791)(9)0.67= 68 cfmQw= 8740(0.001295)(0.43 6.7)1.34= 47 cfmQ is thus 83 cfm = 4960 ft3/h, and the final equation should beI = (4960 ft3/h)/(14,200 ft3) = 0.35 achp. 17.12-13, Fig. 1. The corrected figure is shown on p. A.3.p. 18.35, 2nd col. Just above the Plenu

    17、ms in Load Calculations head-ing, the citation for the UFAD Design Guide should be ASHRAE(2013).p. 18.41, 1st col. In equation for q15, the last term on the first lineshould be c23qi,16.p. 18.49, References. Delete the Bauman and Daly 2013 source, andreplace it with the following:ASHRAE. 2013. Under

    18、floor air distribution (UFAD) design guide, 2nd ed.p. 20.1, 1st col. Immediately after the bulleted list, change theparagraph as follows: “As shown in Figure 1, local temperatureconcentration has a similar profile, although its rate usually dif-fers. Carbon dioxide (CO2) follows a similar pattern.”p

    19、p. 21.7-8. Renumber Figure 10 (Diffuser Installation Suggestions)as Figure 9, and Figure 9 (Friction Chart) as Figure 10.Table 8 Enhanced Model Stack and Wind Coefficients(2013 Fundamentals, Ch. 16, p. 24)One-Story Two-Story Three-StoryNo Flue With Flue No Flue With Flue No Flue With FlueCs0.000891

    20、0.001144 0.001308 0.001478 0.001641 0.001791Cwfor basement slab 0.001313 0.001194 0.001432 0.001313 0.001432 0.001402Cwfor crawlspace 0.001074 0.001074 0.001194 0.001194 0.001271 0.001295Fig. 3 Indirect Evaporative Cooling (IEC) Heat Exchanger(Courtesy Munters/Des Champs)(2012 HVAC Systems and Equip

    21、ment, Ch. 41, p. 3. Replaces only parts B and C of Fig. 3.)Fig. 25 Typical Sensible Storage Connection Scheme(2012 HVAC Systems and Equipment, Ch. 51, p. 24)20122014 ASHRAE Handbook Additions and Corrections A.3p. 21.21, 2nd col., 3rd para. from bottom. The reference to Figure16 should be to Figure

    22、21, and the reference to Figure 10 should beto Figure 9.p. 21.22, step 9c. The correct section in ASHRAE Standard 90.1 is6.5.3.1.p. 22.2, 2nd col. Change “(Table 8 and Figure 7)” to “(Tables 6 and10).”p. 23.18, definitions for Eq. (8). The symbol for outer radius shouldbe r2; for inner radius, it should be r1.2014 Refrigerationp. 12.31, Fig. 68. The source for this graphic should be Seeton et al.2000.p. 24.6, definitions for Eq. (16). In the definition for qs/A, the ref-erence should be to Figure 9.Fig. 1 Example House(2013 Fundamentals, Ch. 17, p. 12)


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