AASHTO HB-17 DIVISION I-A SEC 7-2002 Division I-A Seismic Design - Design Requirements for Bridges in Seismic Performance Categories C and D (Errata 01 2003)《抗振设计-抗震性能范围C和D的桥梁设计要求》.pdf
《AASHTO HB-17 DIVISION I-A SEC 7-2002 Division I-A Seismic Design - Design Requirements for Bridges in Seismic Performance Categories C and D (Errata 01 2003)《抗振设计-抗震性能范围C和D的桥梁设计要求》.pdf》由会员分享,可在线阅读,更多相关《AASHTO HB-17 DIVISION I-A SEC 7-2002 Division I-A Seismic Design - Design Requirements for Bridges in Seismic Performance Categories C and D (Errata 01 2003)《抗振设计-抗震性能范围C和D的桥梁设计要求》.pdf(12页珍藏版)》请在麦多课文档分享上搜索。
1、Section 7 DESIGN REQUIREMENTS FOR BRIDGES IN SEISMIC PERFORMANCE CATEGORIES C AND D 7.1 GENERAL Bridges classified as either SPC C or SPC D in accor- dance with Table 1 of Article 3.4 shall conform to all the requirements of this Section. 7.2 DESIGN FORCES FOR SEISMIC PERFORMANCE CATEGORIES C AND D
2、Two sets of design forces are specified in Articles 7.2.1 and 7.2.2 for bridges classified as Category C or D. The design forces for the various components are specified in Articles 7.2.3 through 7.2.7. 7.2.1 Modified Design Forces Design forces shall be determined as in Articles 7.2.1(A) and 7.2.1(
3、B). Note that for columns a maximum and minimum axial force shall be calculated for each load case by taking the seismic axial force as positive and negative. 7.2.1(A) ModiJed Design Forces for Structural Members and Connections Seismic design forces specified in this Article shall apply to: (a) The
4、 superstructure, its expansion joints and the connections between the superstructure and the sup- porting substructure. (b) The supporting substructure down to the base of the columns and piers but not including the footing, pile cap, or piles. (c) Components connecting the superstructure to the abu
5、tment. Seismic design forces for the above components shall be detehined by dividing the elastic seismic forces ob- tained from Load Case 1 and Load Case 2 of Article 3.9 by the appropriate Response Modification Factor of Arti- cle 3.7. The modified seismic forces resulting from the two load cases s
6、hall then be combined independently with forces from other loads as specified in the following group loading combination for the components. Note that the seismic forces are reversible (positive and negative) and the maximum loading for each component shall be calcu- lated as follows: Group Load = l
7、.O(D + B + SF + E + EQM) (7-1) where, D = dead load B = buoyancy SF = stream-flow pressure E = earth pressure EQM = elastic seismic force for either Load Case 1 or Load Case 2 of Article 3.9 modified by dividing by the appropriate R-Factor. Each component of the structure shall be designed to withst
8、and the forces resulting from each load combination according to Division I, and the additional requirements of this chapter. Note that Equation (7-1) shall be used in lieu of the Division I, Group VI1 group loading combina- tion and that the y and factors equal 1. For Service Load Design, a 50% inc
9、rease is permitted in the allowable stresses for structural steel and a 33% increase for rein- forced concrete. 7.2.I(B) Seismic design forces for foundations, including foot- ings, pile caps, and piles shall be the elastic seismic forces obtained from Load Case 1 and Load Case 2 of Article 3.9 divi
10、ded by the Response Modification Factor (R) speci- fied below. These modified seismic forces shall then be combined independently with forces from other loads as specified in the following group loading combination to determine two alternate load combinations for the foundations. ModiJed Design Forc
11、es for Foundations 465 466 HIGHWAY BRIDGES 7.2.1(B) Group Load = l.O(D + B + SF + E + EQF) (7-2) where D, B, E, and SF are as defined in Article 7.2.1 and EQF = the elastic seismic force for either Load Case 1 or Load Case 2 of Article 3.9 divided by an R- Factor equal to 1 .O. Each component of the
12、 foundation shall be designed to resist the forces resulting from each load combination according to the requirements of Division I and to the additional requirements of Article 7.2.6. 7.2.2 Forces Resulting from Plastic Hinging in the Columns, Piers, or Bents The force resulting from plastic hingin
13、g at the top and/or bottom of the column shall be calculated after the preliminary design of the columns is complete. The forces resulting from plastic hinging are recommended for de- termining design forces for most components as specified in Articles 7.2.3 through 7.2.6. Alternate conservative de-
14、 sign forces are specified if forces resulting from plastic hinging are not calculated. The procedures for calculating these forces for single column and pier supports and bents with two or more columns are given in the following subsections. 7.2.2(A) Single Columns and Piers The forces shall be cal
15、culated for the two principal axes of a column and in the weak direction of a pier or bent as follows: Step 1. Determine the column overstrength plastic moment capacities. For reinforced concrete columns, use a strength reduction factor (+) of 1.3 and for structural steel columns use 1.25 times the
16、nominal yield strength. (Note: This corresponds to the normal use of a strength reduction factor for reinforced concrete. In this case it pro- vides an increase in the ultimate strength.) For both mate- rials use the maximum elastic column axial load from Article 3.9 added to the column dead load. S
17、tep 2. Using the column overstrength plastic mo- ments, calculate the corresponding column shear force. For flared columns this calculation shall be performed using the overstrength plastic moments at both the top and bottom of the flare with the appropriate column height. If the foundation of a col
18、umn is significantly below ground level, consideration should be given to the possibility of the plastic hinge forming above the foundation. If this can occur the column length between plastic hinges shall be used to calculate the column shear force. The forces corresponding to a single column hingi
19、ng are: (a) Axial Forces-unreduced maximum and mini- mum seismic axial load of Article 3.9 plus the dead load. (b) Moments-as calculated in Step 1. (c) Shear Force-as calculated in Step 2. 7.2.2(B) Bents with Two or More Columns The forces for bents with two or more columns shall be calculated both
20、in the plane of the bent and perpendicular to the plane of the bent. Perpendicular to the plane of the bent the forces shall be calculated as for single columns in accordance with Article 7.2.2(A). In the plane of the bent the forces shall be calculated as follows: Step 1. Determine the column overs
21、trength plastic moment capacities. For reinforced concrete use a strength reduction factor (4) of 1.3 and for structural steel use 1.25 times the nominal yield strength. (Note: This corresponds to the normal use of a strength reduction factor for rein- forced concrete. In this case it provides an in
22、crease in the ultimate strength.) For both materials use the axial load corresponding to the dead load. Step 2. Using the column overstrength plastic mo- ments calculate the corresponding column shear forces. Sum the column shears of the bent to determine the max- imum shear force for the bent. Note
23、 that, if a partial-height wall exists between the columns, the effective column height is taken from the top of the wall. For flared columns and foundations below ground level, see Article 7.2.2(A) Step 2. For pile bents the length of pile above the mud line shall be used to calculate the shear for
24、ce. Step 3. Apply the bent shear force to the top of the bent (center of mass of the superstructure above the bent) and determine the axial forces in the columns due to over- turning when the column overstrength plastic moments are developed. Step 4. Using these column axial forces combined with the
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