ASHRAE IJHVAC 2-1-1996 International Journal of Heating Ventilating Air-Conditioning and Refrigerating Research《供暖 通风 空调和制冷研究的国际期刊 第2卷第1号 1996年1月》.pdf
《ASHRAE IJHVAC 2-1-1996 International Journal of Heating Ventilating Air-Conditioning and Refrigerating Research《供暖 通风 空调和制冷研究的国际期刊 第2卷第1号 1996年1月》.pdf》由会员分享,可在线阅读,更多相关《ASHRAE IJHVAC 2-1-1996 International Journal of Heating Ventilating Air-Conditioning and Refrigerating Research《供暖 通风 空调和制冷研究的国际期刊 第2卷第1号 1996年1月》.pdf(107页珍藏版)》请在麦多课文档分享上搜索。
1、1 I I n t e i- n a tio n a 1 J o u i. n al of H e at in g,Veii t i la t in g , Air-conditioning and Refrigerating Research HVAC 6r, . The average cost for the service cycle can then be expressed as a The analysis can be further simplified by assuming that the longest period for the natural driving c
2、onditions %t) is one year. In this study, typical meteorological year (TMY) Hall et al. 1978) weather data were used in the simulations and the typical years weather pattern reoccurred each year. With this simplification, the table only requires n,-n, elements (K31 15 n, 1 I k I n,) and the duration
3、 of the service cycle Tc is an integer multiple of one year. ASHRAE TITLE*IJHVAC 2-1 9b 0759b50 05LBB37 234 = VOLUME 2. NUMBER 1. JANIJARY 1996 7 Given a model for determining Px( t)J( t) needed to calculate Kfi 1 2 1 5 ns, 1 5 k I %), the cost ratio CJC, and the minimum service interval At, the opt
4、imization problem can be defined as minimizing JI with respect to (Te, Ne, tll and the number of time stages between service tasks -8. This is an N, + 2 dimensional optimization problem. The minimum service internal At can be the minimum reaction time of the service orga- nization or a sufficiently
5、small quantity such that the minimum cost no longer depends on its value. In the latter case, At would be decreased until the minimum cost became insensitive to At. For the cleaning of heat exchangers, a minimum service interval of 1 month is a realistic and sufficiently accurate interval for schedu
6、ling service that was used in this study. The optimal maintenance scheduler minimizes the lifetime costs of energy and ser- vice while maintaining comfort, safety, and environmental protection as constraints. These constraints are maintained by adding artificially high costs to the tabulated energy
7、usage IC: for operating conditions that would result in constraint violations. The numerical solution to the optimization problem is accomplished using a combina- tion of two numerical techniq%e:. Given values of T, N, t,. the optimal set of time stages between service tasks ST = S.t;,St;, ., ST_, i
8、s determined using dynamic programming (Bellman 1957). An outer loop, containing the dynamic programming solu- tion. is then used to find the optimal values of the other three quantities: q, NE, T; . Dynamic Programming The use of dynamic programming for solving an optimal equipment replacement prob
9、lem is discussed in Jardine (1973. section 4.41. Dynamic programming determines a global minimum in an efficient manner for this type of problem by taking advantage of the fact that the number of possible solutions is restricted by the sequential nature of the decision process. Ra0 1984) offers a go
10、od description of dynamic programming. Figure 2 is a black box diagram illustrating the sequence of decisions required to solve for the optimum placement of N, service tasks among n, time stages, starting at time stage T. There are Ne - 1 decisions that have to be made and each one is referred to as
11、 a decision stage. The state information passed between decision stages is the time stage that service was last performed ti. for the ith stage). The decision variable is the number of time stages to wait until the next service cazi, for the ith stage). The cost of each decision stage (ci), except t
12、he last, is the energy used while running the unit forari time stages starting at q plus the service cost divided by the energy cost. The cost of the last decision stage ( CNc - 1 ) also includes the energy consumed while running the unit back to the first decision stage plus the cost of the first s
13、enrice task normalized by the energy cost. Finally, the output of each stage is the time of the last service plus the run time for that decision stage = T +a ti). The sum of the costs of the decision stages is given by Dynamic programming is appropriate for this optimization problem because the per-
14、 formance of the vapor compression equipment does not depend on the chain of events that led to the most recent servicing. Figure 2 illustrates this point in that the decision to do service only requires knowledge of the time of the previous service task repre- sented by the state variable passed be
15、tween decision stages). This property of the opti- mal servicing problem guarantees an optimal solution without the need for testing all possible service schedules. Figure 3 illustrates an example dynamic programming problem for optimal mainte- nance scheduling. The abscissa contains the decisions s
16、tages and the ordinate contains ASHRAE TITLEWIJHVAC 2-1 96 0759650 0538838 170 H WAC- RESEARCH 8 4 Figure 2. Dynamic programming places iv, - 1 service tasks to minimize Ji the time stages when service can be done. In this example, there are n, = 12 time stages in a T, = 1 year service cycle (i.e se
17、rvice opportunities are at monthly intervals and the cycle repeats each year). There are N, = 4 service tasks to place and the time stage of the first task is specified as il = 3. The open circles indicate the available opportunities for doing service at each decision stage. Not all values are allow
18、ed for each stage because ii+l is restricted by definition to follow ii. This reduces the number of possible decisions to test, thereby reducing computation time. In general, the number of avail- able time stages at each decision stage is nc - N, + 1. W u U 2 3 4 1 2 Decision Stage Figure 3. Optimal
19、 trajectory through domain for an example problem The example problem of Figure 3 is solved by starting at decision stage 1 and pro- gressing backwards one decision at a time until decision stage 1 is reached again and the cycle repeats itself. Beginning at decision stage 1 where service is performe
20、d at time stage 3). the costs of getting there from all nine allowed time stages in decision stage 4 are computed and stored. Next, all possible time stages in decision stage 3 are considered. For each of these nine time stages, the costs of moving to each possible time stage in decision stage 4 are
21、 computed. Then. the minimum costs-to-go from each of the nine time stages at decision stage 3 to decision stage 1 are computed and stored with the associated path. This process is repeated until decision stage 1 is reached. ASHRAE TITLEMIJHVAC 2-1 96 0759650 0518839 007 where g I 4.2 4.4 4.6 4.8 5
22、tf (years) 1.5 1 .o 0.8 - ;ii . % 0 ._ 0.6 e P 2 6 v al I 0.4 .8 07 0.2 20.0 (b) PLF, = 0.80 Figure 7. Portion of constrained only solution plotted in Figure 6 included and are referenced to the right axes. The service rate is the average number of services per year computed over one service cycle.
23、Dotted vertical lines indicate when the service rate changes. The primary causes of the irregular nature of the cost curves are discontinuities due to sudden changes in service costs when the service rate changes followed by changing energy costs as the fouling time changes for a constant service ra
24、te. Secondary causes of irregular behavior in the cost curves are discrete changes in the month service is performed with the same service rate) and changes in the constraint violation that triggers the service. Both of these secondary features are included in these figures. For example, when PLF, =
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