[外语类试卷]GRE（QUANTITATIVE）练习试卷8及答案与解析.doc

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1、GRE（ QUANTITATIVE）练习试卷 8及答案与解析 1 108 _ 9=12 2 7 _ 2=3.5 3 4 When 5 consecutive odd integers, each greater than 34 are added, what is the smallest possible sum? 5 What is the Lowest Common Denominator of 5/8 and 3/4? GRE（ QUANTITATIVE）练习试卷 8答案与解析 1 【正确答案】 In order for 12 to be the result of this oper

2、ation, you must divide 108 by 9. Insert the symbol in the blank. 2 【正确答案】 To reach an answer of 3.5, you must divide 7 by 2. Insert the + symbol in the blank. 3 【正确答案】 One way to solve this problem is to look for the Lowest Common Denominator (LCD). The smallest number that both 4 and 8 divide evenl

3、y into is 8, so the fraction 3/8 does not need to be changed. The fraction 1/4 is equivalent to 2/8;2/8 plus 3/8 equals 5/8 , so insert the+ symbol in the blank. 4 【正确答案】 To find the smallest possible sum, take the 5 consecutive odd integers that are the closest to 34 (remember, they all must be gre

4、ater than 34). These numbers would be: 35, 37, 39, 41, and 43. Add them together: 35+37+39+41+43=195. 5 【正确答案】 The Lowest Common Denominator (LCD) is the smallest number into which all of the denominators will divide evenly. For this problem, you must find the smallest number into which 8 and 4 will divide evenly. Since 4 will divide evenly into 8(8/4=2), 8 is the LCD.