【计算机类职业资格】(A)二级JAVA笔试-2及答案解析.doc

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1、(A)二级 JAVA 笔试-2 及答案解析(总分：100.00，做题时间：90 分钟)一、基本操作题(总题数：1，分数：30.00)1.本题的功能是计算 110 之间除了 5 以外的各个自然数的和。public class java1public static void main(String args)int i=l;int sum=0;while(i=10)if(i=5)_;_;i+;System. out. println(“sum=“+sum);（分数：30.00）填空项 1:_二、简单应用题(总题数：1，分数：30.00)2.本题的功能是监听键盘敲击事件，并将敲击的字符显示在标签上。

2、开始，文字标签提示“Please press your keyboard!”，当按下键盘上的字符键，文字标签就变为“*is pressed!”(*为所按字母)。import java. awt. * ;import java. awt. event. * ;import javax. swing. * ;public class java2 extends Frame_public static void main(String args)java2 f=new java2(“java2“);Panel pan=new Panel();f. init();public java2(String

3、 str)super(str);public void init()addWindowListener(new WindowAdapter()public void windowClosing(WindowEvent e)System. exit(0););setSize(200,200);setLayout(new FlowLayout();lab=new Label(“Please press your keyboard!“);add(lab);addKeyListener(this);setVisible(true);public void keyTyped(KeyEvent e)lab

4、. setText(“/“+_+“/is pressed !“);repaint();public void keyPressed(KeyEvent e)public void keyReleased(KeyEvent e)private Label lab;（分数：30.00）填空项 1:_三、综合应用题(总题数：1，分数：40.00)3.本题的功能是求两个交叉图形的并、减、交和异或。窗口中有 4 个单选按钮和一个图形面板，面板中有两个交叉的图形，选中其中一个单选按钮，图形面板中以黑色填充的方式显示运算结果。import java. awt. * ;import java. awt. eve

5、nt. * ;import java. awt. geom. * ;import java. util. * ;import javax. swing. * ;public class java3public static void main(String args)JFrame frame=new AreaTestFrame();frame. setDefaultCloseOperation (JFrame. EXIT_ON_CLOSE);frame. show();class AreaTestFrame extends JFramepublic AreaTestFrame()setTitl

6、e(“java3“);setSize(WIDTH, HEIGHT);area1=new Area (new Ellipse2D. Double(100,100,150,100);area2= new Area(new Rectangle2D. Double(150,150,150,100);Container confentPane=getContentpane();panel=newJPanel()public void paintComponent(Graphics g)super, paintComponent(g);Graphics2D g2=(Graphics2D)g;g2. dra

7、w(area1);g2. draw(area2);if(area!=null) g2. fill(area);contentPane, add (panel, BorderLayout. CENTER);JPaneI buttonPanel=new JPanel();ButtonGroup group=new ButtonGroup();JRadioButton addButton=new JRadioButton(“并“, false);buttonPanel. add(addButton);group. add(addButton);addButton. addActionListener

8、(newActionListener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. add(area2);panel. repaint(););JRadioButton subtractButton=new JRadioButton(“减“, false);buttonPanel. add(subtraetButton);group. add(subtractButton);subtractButton. addActionListener(new ActionList

9、ener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. subTract(area2);panel, repaint(););JRadioButton intersectButton=new JRadioButton(“交“, false);buttonPanel. add(interseetButton);group. add(intersectButton);intersectButton. addActionListener(newActionListener()

10、public void actionPerformed(AetionEvent event)area=new Area();area. add(area1);area. intersect(area2);panel. repaint(););JRadioButton exclusiveOrButton=new JRadioButton(“异或“, false);buttonPanel. add(exclusiveOrButton);group. add(exclusiveOrButton);exclusiveOrButton, addActionListener (new ActionList

11、ener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. exclusiveor(area2);panel, repaint(););contentPane, add(buttonPanel, BorderLayout. NORTH);private JPanel panel;private Area area;private Area area1;private Area area2;private static final int WIDTH=400;private

12、static final int HEIGHT=400;（分数：40.00）填空项 1:_(A)二级 JAVA 笔试-2 答案解析(总分：100.00，做题时间：90 分钟)一、基本操作题(总题数：1，分数：30.00)1.本题的功能是计算 110 之间除了 5 以外的各个自然数的和。public class java1public static void main(String args)int i=l;int sum=0;while(i=10)if(i=5)_;_;i+;System. out. println(“sum=“+sum);（分数：30.00）填空项 1:_ （正确答案：第 1

13、 处：i=i+1 或 i+或 i+=1第 2 处：continue第 3 处：sum+=i 或 sum=sum+i）解析：解析 第 1 处 while 循环是累加 110 之间除了 5 的自然数之和，将 i 加 1 是为了跳过 5；第 2处当 i 等于 5 时就跳出本次循环；第 3 处累加 110 之间除了 5 的自然数的和将其最终赋给 sum。二、简单应用题(总题数：1，分数：30.00)2.本题的功能是监听键盘敲击事件，并将敲击的字符显示在标签上。开始，文字标签提示“Please press your keyboard!”，当按下键盘上的字符键，文字标签就变为“*is pressed!”(

14、*为所按字母)。import java. awt. * ;import java. awt. event. * ;import javax. swing. * ;public class java2 extends Frame_public static void main(String args)java2 f=new java2(“java2“);Panel pan=new Panel();f. init();public java2(String str)super(str);public void init()addWindowListener(new WindowAdapter()p

15、ublic void windowClosing(WindowEvent e)System. exit(0););setSize(200,200);setLayout(new FlowLayout();lab=new Label(“Please press your keyboard!“);add(lab);addKeyListener(this);setVisible(true);public void keyTyped(KeyEvent e)lab. setText(“/“+_+“/is pressed !“);repaint();public void keyPressed(KeyEve

16、nt e)public void keyReleased(KeyEvent e)private Label lab;（分数：30.00）填空项 1:_ （正确答案：第 1 处：implements KeyListener第 2 处：e. getKeyChar()）解析：解析 第 1 处实现键盘监听接口；第 2 处键盘事件对象 e 调用 getKeyChar()方法获得用户按下的键盘键值。三、综合应用题(总题数：1，分数：40.00)3.本题的功能是求两个交叉图形的并、减、交和异或。窗口中有 4 个单选按钮和一个图形面板，面板中有两个交叉的图形，选中其中一个单选按钮，图形面板中以黑色填充的方式显

17、示运算结果。import java. awt. * ;import java. awt. event. * ;import java. awt. geom. * ;import java. util. * ;import javax. swing. * ;public class java3public static void main(String args)JFrame frame=new AreaTestFrame();frame. setDefaultCloseOperation (JFrame. EXIT_ON_CLOSE);frame. show();class AreaTestF

18、rame extends JFramepublic AreaTestFrame()setTitle(“java3“);setSize(WIDTH, HEIGHT);area1=new Area (new Ellipse2D. Double(100,100,150,100);area2= new Area(new Rectangle2D. Double(150,150,150,100);Container confentPane=getContentpane();panel=newJPanel()public void paintComponent(Graphics g)super, paint

19、Component(g);Graphics2D g2=(Graphics2D)g;g2. draw(area1);g2. draw(area2);if(area!=null) g2. fill(area);contentPane, add (panel, BorderLayout. CENTER);JPaneI buttonPanel=new JPanel();ButtonGroup group=new ButtonGroup();JRadioButton addButton=new JRadioButton(“并“, false);buttonPanel. add(addButton);gr

20、oup. add(addButton);addButton. addActionListener(newActionListener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. add(area2);panel. repaint(););JRadioButton subtractButton=new JRadioButton(“减“, false);buttonPanel. add(subtraetButton);group. add(subtractButton);

21、subtractButton. addActionListener(new ActionListener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. subTract(area2);panel, repaint(););JRadioButton intersectButton=new JRadioButton(“交“, false);buttonPanel. add(interseetButton);group. add(intersectButton);inters

22、ectButton. addActionListener(newActionListener()public void actionPerformed(AetionEvent event)area=new Area();area. add(area1);area. intersect(area2);panel. repaint(););JRadioButton exclusiveOrButton=new JRadioButton(“异或“, false);buttonPanel. add(exclusiveOrButton);group. add(exclusiveOrButton);excl

23、usiveOrButton, addActionListener (new ActionListener()public void actionPerformed(ActionEvent event)area=new Area();area. add(area1);area. exclusiveor(area2);panel, repaint(););contentPane, add(buttonPanel, BorderLayout. NORTH);private JPanel panel;private Area area;private Area area1;private Area a

24、rea2;private static final int WIDTH=400;private static final int HEIGHT=400;（分数：40.00）填空项 1:_ （正确答案：第 1 处：Container contentPane=getContentPane()第 2 处：area. subtract(area2)第 3 处：area. exelusiveOr(area2)）解析：解析 第 1 处用 getContentPane()获得内容面板；第 2 处表示从 area 形状中减去 area2 形状；第 3 处将 area 设置为 area 形状和 area2 形状的组合，并减去相交部分。