1、IEEE Std 421.5-2005InterpretationIEEE Standards Interpretation for IEEE Std 421.5 -2005IEEE Recommended Practice for Excitation System Models for Power System Stability Studies Copyright 2008 by the Institute of Electrical and Electronics Engineers, Inc. 3 Park Avenue New York, New York 10016-5997 U
2、SA All Rights Reserved.This is an interpretation of IEEE Std 421.5-2005. Interpretations are issued to explain and clarify the intent of a standard and are not intended to constitute an alteration to the original standard or to supply consulting information. Permission is hereby granted to download
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4、EEE Standards Department Copyrights and Permissions 445 Hoes Lane Piscataway, New Jersey 08855-1331, USAApril 2008Interpretation #1 Topic: Limit in Section “5: Type DC-Direct current commutator excitors“I have a question regarding IEEE Std 421.5-2005, in section “5. Type DC-Direct current commutator
5、 exciters“.All of the block diagrams in this section (Figures 5-1, 5-2, 5-3, and 5-4) have a minimum limit http:/standards.ieee.org/reading/ieee/interp/421.5-2005.html (1 of 2) 2009/01/06 7:17:24 PMIEEE Std 421.5-2005Interpretationdrawn on the 1/sTE block. However, the text does not discuss this lim
6、it at all. Figures 5-1, 5-2, and 5-3 do not even label this limit. Figure 5-4 labels it VEMIN. For the DC1A, DC2A, and DC3A models, how should this limit be implemented? What is the range of values it could have?During an extended high voltage condition, this could have an important impact on the ge
7、nerator response.Interpretation Response #1The negative limit on a dc generator is solely based on the total flux of its field windings. The cases to consider are as follows:1) Separately-excited by thyristor or PWM bridge. In this case, field current has a lower limit of 0 and this is also the lowe
8、r limit of the dc voltage.2) Self-excited dc generator with separate control windings (e.g. buck/boost). If the buck winding turns and source (e.g. mag amp) can produce enough flux to overcome the positive flux of the self-excited shunt field, then the total field can be reversed and negative output
9、 is possible.Determining this level requires either measurements or a knowledge of the turns ratio of the various field windings and the source current capability of the device feeding the buck/boost windings.I have only encountered one system where we were able to measure negative output through te
10、sting. In most cases, the buck/boost windings do not have the capacity to overcome the shunt excitation unless it is already very low.Copyright 2008 IEEE. All rights reserved.Back to Available IEEE Standards Interpretations Online Copyright IEEE-SA Contact IEEE-SA For questions or comments, please contact the IEEE-SA Webmaster. http:/standards.ieee.org/reading/ieee/interp/421.5-2005.html (2 of 2) 2009/01/06 7:17:24 PM